6. Insert 5 Am's between 5 and 35.
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Inserting 5 arithmetic means between two numbers, we can produce the total number of terms equal to 7. So the given data are:
a1=3, an=27, n= 7 where a1= 1st term, an=last term and n= number of terms.
Solving for the common difference, d:
Formula: an=a1+(n-1)d
27=3+(7–1)d= 3+6d, 6d=27–3=24, d=24/6
d= 4 is the common difference
Given numbers in A.M. are: 3, . . . . . . 27
5 A.M. numbers inserted having the common difference of 4 are 7, 11, 15, 19, 23.
And the complete A.M. numbers having a common difference of 4 are 3, 7, 11, 15, 19, 23, 27.
Step-by-step explanation:
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