Question

6. Interest on 12000 for 2years at the rate of 10% per annum
(1 Point​

Answer 1

Here P=12,000 Rs., n=2 years, R=10

Amount(A)=P(1+

100

R

)

n

=12000(1+

100

10

)

2

=12000(

10

11

)

2

=

100

12000×121

=14,520 Rs.

Compound interest(C.I)=A−P=14,520−12,000=2520

Hence, the compound interest is Rs. 2,520

Answer 2

Before, finding the answer. Let's find out on how we can find the answer.

• To find the Simple Interest by using the formula of :

$\sf S.I = \dfrac{p \times r \times t}{100}$

Where,

P = Principal

R = Rate

T = Time

• Here, we have to first multiply the Principal, Rate and Time.
• Then, we must divide it by 100.

__________________

Given :

• Principal = 12000
• Rate = 10%
• Time = 2

To find :

Simple Interest

Solution :

We know that,

$\sf S.I = \dfrac{p \times r \times t}{100}$

$\sf = \dfrac{12000 \times 10 \times 2}{100}$

$\sf = \dfrac{2400 \cancel0 \cancel0}{1 \cancel0 \cancel0}$

$\sf = 2400$

Hence, Simple Interest is Rs. 2400.

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