Question

6.
It is given that in a group of 3 students, the probability of 2 students not having the sam
birthday is 0.992. What is the probability that the 2 students have the same birthday​

Answer 1

Answer:

Plz brainly me hightest marks dena!

Answer 2

Answer:

Hey friend here is ur answer

Step-by-step explanation:

Let A = Event that two students do not have same birthday

Therefore, P(A) = 0.992

So, probability of two students having same birthday P(B)=1–P(A)

P(B)=1–0.992

P(B)= 0.008

Hope this helps you