Question

-
6 J
Work done = Energy given
3. 6 joule of work is done in moving 18.75 X 10's electrons from one
end to the other end of a conductor. What is the potential
difference between the two end of conductor?​

Answer 1

Step-by-step explanation:

For 1 C charge, the number of electrons required are 6.25×10-¹⁸

Therefore, when 18.75×10-¹⁸

electrons are moving, corresponding charge is Q=3 C

work done = Q/V

Then,

V= W/Q

V = 3.6 / 18.75×10-¹⁸