Question

(6) Jaya runs four times around a square field of side 74 m. Paya runs three times
around a rectangular field of length 130 m and breadth 72 m. Who covers more
distance and by how much?​

Answer 1

Answer:

Paya > Jaya

Paya = 1.212 m

Jaya = 1.184 m

Step-by-step explanation:

JAYA

• Find the perimeter of the square

Formula :

$\boxed{\bf{P_{square}=4\times s}}$

s = side of square

$\begin{aligned}\rm{P}&\rm{=4s}\\&\rm{=4\times74}\\&\rm{=296~m}\end{aligned}$

• Find the Jaya's distance

→Jaya runs four times, so the distance/space is 4P.

$\begin{aligned}\rm{s}&\rm{=4P}\\&\rm{=4\times 296\\&\rm{=1.184~m}}\end{aligned}$

Paya

• Find the perimeter of the rectangular

Formula :

$\boxed{\bf{P_{rectangular}=2\times(l+w)}}$

l = length of rectangular

w = width of rectangular

$\begin{aligned}\rm{P}&\rm{=2(l+w)}\\&\rm{=2(130+72)}\\&\rm{=2\times202~m}\\&\rm{=404~m}\end{aligned}$

• Find the Paya's distance

→Paya runs three times, so the distance/space is 3P.

$\begin{aligned}\rm{s}&\rm{=3P}\\&\rm{=3\times 404\\&\rm{=1.212~m}}\end{aligned}$

Conclusion

From that, we can know that Paya covers more distance than Jaya.

Paya > Jaya

1.212 m > 1.184 m