Question

6. K_Cr2O7 + SO2 + H2SO4
-> (
K,SO4 + Cr2(SO4)3 + H,0 by partial equation method
​

Answer 1

K2Cr2O7 + H2SO4 + 3SO2-> K2SO4 + Cr2(SO4)3 + H2O

Explanation:

= K2Cr2O7 + 4H2SO4 -> K2SO4 + Cr2(SO4)3 + 4H2O + negative radicals is 3O

= 3SO2 + 3H2O + 3O -> 3H2SO4

-> K2CR2O7 + H2SO4 + 3SO2 -> K2SO4 + Cr2(SO4)3 + H2O

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