Question

6 kg block is stationary on a horizontal table. The value of μs for the surfaces in contact is 0.6. Find the minimum horizontal force P required to start the sliding motion of the block. If you spam I will report it.​

Answer 1

Explanation:

. Ffric=μsW=0.4∗20=8N

b. Since Fapplied<Ffric

Ffric=5N

c.  Minimum force required to start the motion F=Fstaticfric=8N

d.  Minimum force required to start the motion

F=Fkineticfric=μkW=0.2∗20=4N

e. F>Fstaticfric motion started.

F>Fkineticfric hence motion continues.

Ffric=4N