6. ĽAladder of length 8m is leaning against a wall. Angle made by the ladder with the floor is 70%. [3] (A)Draw a rough sketch?
(B) [ Sin 70°=0.94 , Cos 70°=0.34 , Tan 70°=2.75 ]
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Let AB be the length of the ladder and CA be the wall.
The ladder makes an angle of 60∘ with the horizontal.
∴△ABC is 30∘−60∘−90∘ ,right triangle
We have tan60∘=BCAC
⇒AC=3.5×tan60∘
⇒AC=3.5×3m
From Pythagoras theorem, we have
AB2=BC2+CA2
⇒AB2=(3.5)2+(3.5×3)2
⇒AB2=12.25+36.75
⇒AB2=49
∴AB=7m
I hope it will help you.
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