Question

6. Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and angle B = 90°. BD is the
perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents
from A to this circle.
step by step please​

Answer 1

Step-by-step explanation:

draw a triangle draw a triangle ABC with ab is equal to 6 CM, BC is equal to 8 cm and angle b is equal to 90 , from B draw altitude BD on AC

bisect BC to obtain its midpoint to draw the circle with diameter BC which will pass through D as angle d is equal to 90 degree

draw the circle with Centre a and radius Ab To intersect the previous circle with diameter for BC at E

join AE

then A B and C are required tangent from a to the circle passing through b c and d

Answer 2

Answer:

 So, we draw perpendicular bisector of BC, and find center of circle. ... Join AC ∴ Δ ABC is the required triangle Now, let’s draw a circle and construct tangents Steps to draw circle and tangents Draw perpendicular bisector of line...................