Question

6. Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and Z B = 90°. BD is the
perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents
from A to this circle.
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Answer 1

Answer:

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Answer 2

Answer:

Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B = 90°. BD is the perpendicular from ts on AC. The circle through B, C and D is drawn. Construct the tangents from A to the circle..

Steps of construction:

1. Draw a line segment BC = 8 cm.

2. Make a right angle at the point B i.e., ∠CBX = 90°

3. Draw a are of radius 6 cm as centre B which intersect BX at the point A.

4. Join AC so, ABC is required right angle triangle.

5. Draw a arc taking centre B which intersect AC at the point K and L respectively taking K and L centre draw two arcs of same radius which intersect at the point M.

6. Join BM so, ∠BDC = 90°.

7. Draw perpendicular bisector of BC.

8. Draw a circle taking radius equal to OB and centre O which passes through B, D and C.

9. Draw a arc taking centre A and radius equal to AB intersect the circle at point P so, AP is the tangents.