Question

6. Lime is an alkaline substance. The figure shows some of the properties of a calcium
compound "X". The letters are not chemical symbols of substances. Answer the questions that
follow :
(2)
A colourless compound "X"
Heat
heat
Strongly
White solid "y"
Gas "p"
Mix
Lime water turns
milky
with lime water
Dissolves in water
Add universal
Blue colour
Colourless aqueous
solution "Z"
Indicator
a) Write the chemical reaction and Identify "p"
b) Identify "Z" and write the reaction of "Y" to get "Z"
c) Name an acld which can liberate "p" from "X".
d) Write the reaction of lime water with "P".​

Answer 1

Answer:

a) Here from the above question we can say that the colorless compound x is Sodium Hydrogen Carbonate and the white solid is acetic acid.

• When acetic acid is added to sodium Hydrogen Carbonate then it evolves into the gas CO2 we called it as p.

The reaction is as follows

NaHCO3+ CH3COOH -----> CH3COONa + CO2 + H2O

• CO2 turns lime water milky. It dissolves in a solution of sodium hydroxide.

b) CO2 + H2O --------> H2CO3

Add colorless Phenolphthalein to lime water the liquid turns pink.

c) Acetic acid liberates CO2 from NaHCO3.

d) When CO2 is added to lime water it forms Calcium carbonate.

Ca(OH)2 + CO2 ----------> CaCO3

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Answer 2

Answer:

a) The chemical reaction is the following: CaX + 2H2O → Ca(OH)2 + H2

P is hydrogen gas.

b) Z is a colourless aqueous solution, and the reaction of Y to get Z is as follows: Ca(OH)2 + HCl → CaCl2 + H2O

c) An acid which can liberate P from X is hydrochloric acid (HCl).

d) The reaction of lime water with P is as follows: Ca(OH)2 + H2 → CaX + 2H2O. This reaction is an example of an acid-base neutralization reaction, since H2 is an acid and Ca(OH)2 is a base. When this reaction is carried out, the lime water turns milky due to the formation of tiny particles of calcium carbonate (CaCO3).

For more information related to chemical reactions, click

https://brainly.in/question/6281601

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