Question

-6<5x-1<19
$- 6 < 5x - 1 \leqslant 19$
​

Answer 1

Given, - 6 < 5x - 1 ≤ 19

Adding 1 to the terms, we get

- 6 + 1 < 5x - 1 + 1 ≤ 19 + 1

or, - 5 < 5x ≤ 20

Dividing the terms by 5, we get

- 1 < x ≤ 4

This is the required solution, where - 1 < x ≤ 4.

For integral solutions, For natural solutions,

x = 0, 1, 2, 3, 4 x = 1, 2, 3, 4

For real solutions,

- 1 < x ≤ 4

Answer 2

Answer:

$Given:$

$=> -6 < 5x-1 < 19$

Now

Add 1 to the given equation

so

$=> -6+1 < 5x-1+1 < 19+1$

$=> -5 < 5x < 20$

Now

Divide by 5 the given equation

so

$=> -5/5 < 5x/5 < 20/5$

$=> -1 < x < 4$

$Integral Solution:$

$x = 0,1,2,3,4$

$Natural Solution:$

$x = 1,2,3,4$

$Real Solution:$

$-1 < x < 4$