Question

6. Mahesh sold two cell phones at 9900 each. On one he gained 10% and on the other he lost 10%
Find:
a. the cost price of each cell phone.
b.
the total profit or loss in the whole transaction.
C.
his total profit or loss %.
fit of 120/
At what nice ner ka should he​

Answer 1

Answer:

(a)C.P−?

(b) Total profit loss in ?

(c) Profit on less %

(  

10

10

​  

)  

2

=1% less 10−10  

100

10×10

​  

 

100

1

​  

×2×9900=198 rs loss

Acc. so quest  

n

 

10

11n

​  

+  

10

9n

​  

=9900

10

20n

​  

=9900

2n=9900

n=4950

S.P of 1 Phone =  

10

11×4950

​  

=5445

S.P of 2  

nd

 Phone =  

10

9×4950

​  

=4455

Step-by-step explanation:

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Answer 2

Answer:

a)

1st cellphone =9000

SP =9900

GAIN=10%

CP=100/100+G×SP

CP=100/100+10×9900

CP=100/110×9900

CP=9000

2nd Cellphone=11,000

SP =9900

LOSS=10%

CP=100/100-L×SP

CP=100/100-10×9900

CP=100/90×9900

CP=11,000

b)

Total CP of two cell phones=9000+ 11,000= 20000

Total SP of two cell phones=9900+ 9900

= 19,800

here, CP>SP= loss

Total loss= 20,000-19,800= 200

c)

Loss%= Change in price/original price ×100

Loss %= 200/20000 ×100= 1% Loss

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