6. Mahesh sold two cell phones at 9900 each. On one he gained 10% and on the other he lost 10%
Find:
a. the cost price of each cell phone.
b.
the total profit or loss in the whole transaction.
C.
his total profit or loss %.
fit of 120/
At what nice ner ka should he
Answers
Answer:
(a)C.P−?
(b) Total profit loss in ?
(c) Profit on less %
(
10
10
)
2
=1% less 10−10
100
10×10
100
1
×2×9900=198 rs loss
Acc. so quest
n
10
11n
+
10
9n
=9900
10
20n
=9900
2n=9900
n=4950
S.P of 1 Phone =
10
11×4950
=5445
S.P of 2
nd
Phone =
10
9×4950
=4455
Step-by-step explanation:
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Answer:
a)
1st cellphone =9000
SP =9900
GAIN=10%
CP=100/100+G×SP
CP=100/100+10×9900
CP=100/110×9900
CP=9000
2nd Cellphone=11,000
SP =9900
LOSS=10%
CP=100/100-L×SP
CP=100/100-10×9900
CP=100/90×9900
CP=11,000
b)
Total CP of two cell phones=9000+ 11,000= 20000
Total SP of two cell phones=9900+ 9900
= 19,800
here, CP>SP= loss
Total loss= 20,000-19,800= 200
c)
Loss%= Change in price/original price ×100
Loss %= 200/20000 ×100= 1% Loss
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