6 males and 8 females can do a work in 10 days. 26 males and 48 females can do the same work in 2 days. so, 15 males and 20 females would take how many days to complete the same work?
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Answer:
Time taken by 15 men and 20 women in doing the work = 4 days
Step-by-step explanation:
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 --- (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = 1/2
=> 52m + 96b = 1--- (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
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