Question

6 men and 10 women can finish making pots in 8 days, while the 4 men and 6 women can finish it in 12 days. Find the time taken by the one man alone from that of one woman alone to finish the work.

Answer 1

Given:

6 men and 10 women can finish making pots in 8 days

4 men and 6 women can finish it in 12 days

To find:

Time taken by the one man alone from that of one woman alone to finish the work

Solution:

• Let the work done by 1 man in 1 day = 1/x
• Let the work done by 1 woman in 1 day =  1/y

According to the question:

6 men and 10 women can finish making pots in 8 days

So,

• 6/x + 10/y = 1/8 -------------(I)

4 men and 6 women can finish it in 12 days.

So,

• 4/x + 6/y = 1/12 --------(II)

Take 1/x = M and 1/y = W

On solving the equation (I) and (II) we get:

• M=1/48 , W= 0

So,

x = 48

Then time taken by the one man alone from that of one woman alone to finish the work is 48 days

Answer 2

answer is 48 days i.e, x=48