Math, asked by nikhilakuncham, 2 months ago

6 men and 10 women can finish making pots in 8 days, while the 4 men and 6 women can finish it in 12 days. Find the time taken by the one man alone from that of one woman alone to finish the work.​

Answers

Answered by felicosby8
2

Answer:

answer is 48 days i.e, x=48

Step-by-step explanation:

According to the question:

6 men and 10 women can finish making pots in 8 days

So,

6/x + 10/y = 1/8 -------------(I)

4 men and 6 women can finish it in 12 days.

So,

4/x + 6/y = 1/12 --------(II)

Take 1/x = M and 1/y = W

On solving the equation (I) and (II) we get:

M=1/48 , W= 0

So,

x = 48

Then time taken by the one man alone from that of one woman alone to finish the work is 48 days

(Not my answer btw but its right)

Answered by sumellikaagnisha
2

Given:

6 men and 10 women can finish making pots in 8 days

4 men and 6 women can finish it in 12

days

To find:

Time taken by the one man alone from that of one woman alone to finish the work

Solution:

  • Let the work done by 1 man in 1 day = 1/x

  • Let the work done by 1 woman in 1 day = 1/y

According to the question:

6 men and 10 women can finish making pots in 8 days

So,

  • 6/x + 10/y = 1/8 -----------(1)

4 men and 6 women can finish it in 12 days.

So,

  • 4/x + 6/y = 1/12----(II)

Take 1/x = M and 1/y = W

On solving the equation (I) and (II) we get:

  • M=1/48, V W= 0

So,

x = 48

Then time taken by the one man alone from that of one woman alone to finish the work is 48 days

{ \green{ \boxed{ \pink{ \bf{ hope \:  it  \: helps \:  you}}}}}

{ \green{ \boxed{ \pink{ \bf{please \:  mark  \: me  \: as  \: brainliest }}}}}

{ \blue{ \boxed{\pink{\underline{\green{\underline{ \orange {\bf{ please\: be \:my \:friend}}}}}}}}}

Similar questions