Question

6 men and 10 women can finish making pots in 8 days, while the 4 men and 6 women can finish it in 12 days. Find the time taken by the one man alone from that of one woman alone to finish the work.






Friends answer fast please and no spamming please it's urgent and important ​

Answer 1

Answer:

48 days

Step-by-step explanation:

Given:

6 men and 10 women can finish making pots in 8 days

4 men and 6 women can finish it in 12 days

To find:

Time taken by the one man alone from that of one woman alone to finish the work

Solution:

Let the work done by 1 man in 1 day = 1/x

Let the work done by 1 woman in 1 day =  1/y

According to the question:

6 men and 10 women can finish making pots in 8 days

So,

6/x + 10/y = 1/8 -------------(I)

4 men and 6 women can finish it in 12 days.

So,

4/x + 6/y = 1/12 --------(II)

Take 1/x = M and 1/y = W

On solving the equation (I) and (II) we get:

M=1/48 , W= 0

So,

x = 48

Then time taken by the one man alone from that of one woman alone to finish the work is 48 days

Answer 2

Answer:

48

Step-by-step explanation:

6 men and 10 women can finish making pots in 8 days

4 men and 6 women can finish it in 12 days

To find:

Time taken by the one man alone from that of one woman alone to finish the work

Solution:

Let the work done by 1 man in 1 day = 1/x

Let the work done by 1 woman in 1 day = 1/y

According to the question:

6 men and 10 women can finish making pots in 8 days

So,

6/x + 10/y = 1/8 -------------(I)

4 men and 6 women can finish it in 12 days.

So,

4/x + 6/y = 1/12 --------(II)

Take 1/x = M and 1/y = W

On solving the equation (I) and (II) we get:

M=1/48 , W= 0

So,

x = 48

Then time taken by the one man alone from that of one woman alone to finish the work is 48 days