Question

6 men and 8 boys can do a piece of work in 7 days while 8 men and 12 boys do the same work in 5 days.How long would it take one boy to finish the same work

Answer 1

Answer:

x = 4 so 15 men and 20 boys will have to work for 4 days to complete the job

Step-by-step explanation:

Units of work done is measured in terms of man-days, boy-days etc. you will have to find our the number of man-days and boy-days required to do the job and equate it.

10(6M+ 8B) = 2 (26M + 48B) since the same work is done they will be equal

60M + 80B = 52M + 96B

8M = 16B or M = 2B substitute 2B = M and you will get the total man-days required to do the job and it is

10( 6M + 4M) = 100 man-days

Similarly substitute 20B as 10M to find out the answer

x(15M+10M) = 100M

solving this x = 4 so 15 men and 20 boys will have to work for 4 days to complete the job

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