6 men and 8boys can do a work in 10 days while 26 men and 48 boys can do in 2 days the time taken by 15 mens and 20 boy to do the same tyep of work will be
Answers
Step-by-step explanation:
there are three different conditions are there
condition 1 :-6 men and 8 boys can do a piece of work in 10 days
condition 2:- 26 men and 48 boys can do the same in 2 days
condition 3:- what is time taken by 15 men and 20 boys? we have to find
We will represent boy with men with m
so from condition 1 what is time taken by 15 men and 20 boys?
so will have total available work done in 10 days
10( 6m + 8b ) ……………………………………………………………………eq 1
Same work has been done with condition two i.e 26 men and 48 boys can do the same in 2 days
so will have total available work done in 2 days
2 (26m + 48 b) ……………………………………………………………………eq 2
so we want total work done as per third condition i.e what is time taken by 15 men and 20 boys?
here we dont have time (days) info so we will consider X days
X ( 15m + 20b ) ……………………………………………………………………eq 3
the work done is same in the all conditions but manpower are different
we can wriye eq 1 and eq 2 as
10( 6m + 8b ) = 2 (26m + 48 b)
60m + 80b = 52m + 96b
8m = 16b
m=2b
we can write eq 1 and eq 3 as
10( 6m + 8b ) = X ( 15m + 20b )
10( 12b + 8b) = X (30b + 20b)
200b/ 50b = X
4 = X time taken by 15 men and 20 boys