6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the same piece of work in 10 days. if 4 men, 12 women and 20 children work together for 2 days. if only men were to complete the remaining work in 1 day, how many men would be required totally
Answers
36 Men will be required to complete remaining work in 1 day
Step-by-step explanation:
6 men can complete a piece of work in 12 days
=> work = 6 * 12 = 72 Man days
=> 1 Man 1 day work = 1/72
8 women can complete the same piece of work in 18 days
=> Work = 8 * 18 = 144 Woman days
=> 1 Woman 1 Day work = 1/144
18 children can complete the same piece of work in 10 days
=> Work = 18 * 10 = 180 children days
=> 1 Children 1 day work = 1/180
4 men, 12 women and 20 children work together for 2 days
Work done = 2 ( 4 * 1/72 + 12 * 1/144 + 20 * 1/ 180)
= 2( 1/18 + 1/12 + 1/9)
= 2(2 + 3 + 4)/36
= 18/36
= 1/2
Remaining work = 1 - 1/2 = 1/2
1 Man 1 day work = 1/72
Number of Men required to complete remaining work in 1 Days = (1/2)/(1/72)
= 36
36 Men will be required to complete remaining work in 1 day
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