Question

6 men can complete a piece of work in
14 days. 14 women can complete it in
12 days while 28 children can complete the
same piece of work in 9 days. In how many
days can 8 men, 2 women and 5 children
complete the same piece of work?​

Answer 1

6M×14=14W×12=28C×9

21M=42W=63C

7M=14W=21C

M=2W=3C

L.C.M of 1,2,3 = 6

so M = 6/1= 6 unit/day

W= 6/2= 3unit/day

C=6/3= 2unit/day

so, total work = 6M×14 = 6×6×14= 504 unit

(8M+2W+5C)'s 1 day work = 8×6+2×3+5×2= 64 unit

to complete 504 unit work

time taken = 504/64 = 7.8 days

Answer 2

Step-by-step explanation:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x= Hence, the required number is 57.