6 men can complete a piece of work in
14 days. 14 women can complete it in
12 days while 28 children can complete the
same piece of work in 9 days. In how many
days can 8 men, 2 women and 5 children
complete the same piece of work?
Answers
Answered by
0
6M×14=14W×12=28C×9
21M=42W=63C
7M=14W=21C
M=2W=3C
L.C.M of 1,2,3 = 6
so M = 6/1= 6 unit/day
W= 6/2= 3unit/day
C=6/3= 2unit/day
so, total work = 6M×14 = 6×6×14= 504 unit
(8M+2W+5C)'s 1 day work = 8×6+2×3+5×2= 64 unit
to complete 504 unit work
time taken = 504/64 = 7.8 days
Answered by
1
Step-by-step explanation:
Let the tens digit of the required number be x and the units digit be y. Then,
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2 ..........(2)
On adding (1) and (2), we get,
2y=14⟹y=7
Therefore,
x= Hence, the required number is 57.
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