Math, asked by sujitmondal273, 3 months ago

6 men can do a piece of work in 12 days while 8 women can do the same work in 18 ays , the rest or the whole 1 an finish the ays . In how ficiency ? 18 days to vely Both 12 days . 45 3 leaves 5 more days . The same work can be done by contraveno 10 days . A men , 12 women and 20 children work together for 2 days . If only men have to complete remaining work in 1 day , then find the required number of men .​

Answers

Answered by prabhas24480
2

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1 man will complete the work in = 6 × 12 = 72 days

1 woman will complete the work in = 8 × 18 = 144 days

1 child will complete the work in = 18 × 10 = 180 days

4 men + 12 women + 20 children's 2 days' work

= 2 (472+12144+20180)

= 2 (118+112+19)

= 2(2+3+4)36 = 12

∴ Remaining work = 12

∴ Required number of men

=72×12 = 36

Answered by UniqueBabe
3

1 man will complete the work in = 6 × 12 = 72 days

1 woman will complete the work in = 8 × 18 = 144 days

1 child will complete the work in = 18 × 10 = 180 days

4 men + 12 women + 20 children's 2 days' work

= 2 (472+12144+20180)

= 2 (118+112+19)

= 2(2+3+4)36 = 12

∴ Remaining work = 12

∴ Required number of men

=72×12 = 36

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