Question

6 men or 8 woman can repair a road in 28days.In how much time would 9 men and 2 woman repair the same road

Answer 1

Answer:

16 days

Step-by-step explanation:

If 6 men repair the road in 28 days,

work done by 1 man in 1 day = $\frac{1}{28 X 6}$ = $\frac{1}{168}$

If 8 women repair the road in 28 days,

work done by 1 woman in 1 day = $\frac{1}{28 X 8}$ = $\frac{1}{224}$

If 9 men and 2 women repair the road,

work done in 1 day = (9 X $\frac{1}{168}$) + (2 X $\frac{1}{224}$)

= $\frac{3}{56}$ + $\frac{1}{112}$

= $\frac{7}{112}$

If number of days required to complete the work is N,

N X $\frac{7}{112}$ = 1

N = 16 days

Answer 2

6men = 28 day

= 1/(28 * 6) = 1/168

8women = 28 day

1/(8 * 28) = 1/214

So 9men ond 2 women complete work. = x

(9x1/163) + (2x1/224)

x = 3/56 + 1/112

7/112

16day answer

AB wer