6 moles of ammonia and 2 moles of hcl are dissolved in 0.8 litre aqueous solution . calculate ph of the solution (ka for ammonium ion 5.55x10^-10)
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Explanation:
NH
3
+H
2
O
k
b
⇌
k
f
NH
4
+
+OH
−
;K
b
=3.4×10
10
NH
4
+
+H
2
O⇌NH
4
OH+H
+
;K
a
=5.6×10
−10
K
Base
=
k
b
k
f
=
K
Acid
K
w
...(i)
K
Acid
×K
Base
=K
w
3.4×10
10
k
f
=
5.6×10
−10
10
−14
k
f
=6.07×10
5
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