Question

6 moles of na2co3 is reacted with 4 moles of hci solution. Find the volume of co2 gas produced at ntp.

Answer 1

Answer:CaCO3 + 2HCl → CaCl2 + CO2 + H2O

This equation tells you that for every mol of CaCO3 consumed you will be producing 1 mol of CO2. In other words there is a 1:1 relationship between CaCO3 and CO2.

The next step is to determine the amount of CaCO3 you have in moles, and since HCl is in excess, you do not need to worry about which one is the limiting reagent (CaCO3 is limiting since HCl is in excess).

Explanation:

Answer 2

Answer:

The answer is 44.8 litres.

Reaction-:

Na2CO3+2HCL->2Nacl+CO2+H2O.

1mole 2mole 2mole 1mole

Given

6mole 4mole

But here 6 moles of Na2CO3 requires 12 moles of HCL.

Hence HCL is the limiting reagent.

Since 2moles of HCL gives 1mole of CO2 or 22.4 litres CO2.

Then 4 moles would give-: 4×22.4/2=44.8 litres.