Question

6 no. if base radius of a right circular cyclinder is halved , keeping the height same find the radius if the reduse cyclinder to tat of the original cyclinder​

Answer 1

Step-by-step explanation:

$so \: let \: radious \: = r \\ and \: height = h \\ first \: radious = r \\ so \: second \: radious = \frac{r}{2} \\ volume \: of \: cylinder = \pi \times {r}^{2} \times h \\ according \: the \: question \\ ratio = \frac{\pi \times ( \frac{r}{2}) {}^{2} \times h }{\pi \times (r) {}^{2} \times h } \\ = \frac{ \frac{ {r}^{2} }{4} }{ {r}^{2} } \\ = \frac{1}{4} \\ so \: ratio = 1ratio4$