6. Notice the given samples a. 20g He b. 44.8 L NH3 at STP c. 67.2 L N2 at STP d. 1 mole H2SO4 e.180g H2O (Molecular mass He = 4 NH3 = 17 N2 = 28 H2SO4 = 98 H2O = 18 ) 1. Arrange the given samples in the increasing order of the number of molecules
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Answer:
20g of He
Mole of He = 20 g/ 4 g/mol
= 5 mol
Therefore, there are 5 mol of He atom.
44.8 L of NH3
Mole of NH3 = 44800 g / 17 g/mol
= 2635.29 mol
1 mole of H2SO4
180 g of H2O
Mole of H2O = 180g / 18g/mol
= 10 mol
Therefore, In increasing order
H2SO4 < He < H2O < NH3
Hence solved.
Thankyou
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