Question

6. Notice the given samples a. 20g He b. 44.8 L NH3 at STP c. 67.2 L N2 at STP d. 1 mole H2SO4 e.180g H2O (Molecular mass He = 4 NH3 = 17 N2 = 28 H2SO4 = 98 H2O = 18 ) 1. Arrange the given samples in the increasing order of the number of molecules

Answer 1

Answer:

20g of He

Mole of He = 20 g/ 4 g/mol

= 5 mol

Therefore, there are 5 mol of He atom.

44.8 L of NH3

Mole of NH3 = 44800 g / 17 g/mol

= 2635.29 mol

1 mole of H2SO4

180 g of H2O

Mole of H2O = 180g / 18g/mol

= 10 mol

Therefore, In increasing order

H2SO4 < He < H2O < NH3

Hence solved.

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