Question

6) On a particular planet, it takes 850 J for a 50 kg remote probe to launch itself up 2 m. What is the gravitational field strength of the planet?

Answer 1

Given:-

• Potential Energy ,PE = 850 J

• Mass ,m = 50 kg

• Height,h = 2 m

To Find:-

•Gravitational field strength ,g

Solution:-

Firstly we calculate the acceleration on the planet

• PE = mgh

where,

PE is Potential Energy

m is the mass

g (a) is the acceleration

h is the height

Substitute the value we get

→ 850 = 50×a × 2

→ 850 = 100×a

→ a = 850/100

→ a = 8.5m/s²

Acceleration is 8.5m/s².

Now, Calculating the Gravitational Field Strength

• g = F/m

where,

F is the force

m is the mass

Substitute the value we get

→ g = ma/m. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀( F = ma)

→ g = 50×8.5/50

→ g = 8.5 N/kg

Therefore,the gravitational field strength is 8.5 N/kg .

Answer 2

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6) On a particular planet, it takes 850 J for a 50 kg remote probe to launch itself up 2 m. What is the gravitational field strength of the planet?

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• $potential \: energy(PE) = 850J$
• $weight(m) = 50kg$
• $height(h) = 2m$

${ { \underbrace{ \mathbb{ \red{To\: PrOvE\ }}}}}$

$gravitational \: field \: strength \: of \: planer (g)$

$\star\underbrace{\mathtt\red{❥ᴀ} \mathtt\green{n }\mathtt\blue{S} \mathtt\purple{W}\mathtt\orange{e} \mathtt\pink{R}}\star\:$

${\boxed {\boxed {PE=mgh}}}$

• $PE=potential\:energy$
• $m=weight$
• $g=(a) acceleration$
• $h=height$

$now \: substitute \: the \: values$

$850 = 50 \times a \times 2$

$850 = 100a$

$a = \frac{850}{100}$

${\boxed {a = 8.5 m/{s}^{2}} }$

$gravitational \: field \: strength$

${\boxed {\boxed {g=\frac{F}{m}$

• $F=force(F=ma)$
• $m=weight$

$substitute \: the \: values$

$g=\frac{ma}{m}$

$g=\frac{50\times 8.5}{50}$

${\boxed {\boxed {g=8.5 N/kg}}}$

$\therefore\: the\: gravitational \:force\: is{\boxed {\boxed {=8.5N/kg}}}$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{Hope\:It\:Helps}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$