6. One bag contains 5 red and 7 black balls and the other 3 red and 12 black balls. A ball is drawn at random from either of the bags. What is the chance that the selected ball is black?
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Answered by
5
total balls = 5+7+3+12= 27 balls
probability of black balls= 12/27
probability of black balls= 12/27
Answered by
0
========
★Solution :
>>>>>>>>(★)<<<<<<<<<<
Total balls:
5 red ,7black,3red and 12 black....
now, total are: 27
no. of black ball=19
p(e) of getting black ball= (total no. of black ball)÷(total no. of ball)
p(e)=19/27
>>>>>>>(★)<<<<<<<<<
=================
^_^
★Solution :
>>>>>>>>(★)<<<<<<<<<<
Total balls:
5 red ,7black,3red and 12 black....
now, total are: 27
no. of black ball=19
p(e) of getting black ball= (total no. of black ball)÷(total no. of ball)
p(e)=19/27
>>>>>>>(★)<<<<<<<<<
=================
^_^
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