Question

-
6.One equation of a pair of
dependent linear equations is
4x + 6y - 2 = 0. The second
equation can be *
-8x+6y-4=0
-12x-18y-12=0
-12x+18y-12=0

-12x+18y-6=0

Answer 1

Answer:

-8x+6y-4=0

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Answer 2

Concept

We will check each of the options if it can be written as in the form of a given equation then the one which can be written as one the given linear equation then that will be the second dependent linear equation.

Given

The first given linear equation is 4x+6y-2=0.

Find

We have to calculate the second dependent linear equation of the first one.

Solution

Let’s check the first option i.e. -8x+6y-4=0

Dividing by 2 we have

-4x+3y-2=0, which is not the same as 4x+6y-2=0.

Now the second option, -12x-18y-12=0

Dividing by 2 , we have

-6x-9y-6=0, which is again not the same as 4x+6y-2=0.

Now the third option is different only in sign, therefore it also can’t be written as 4x+6y-2=0.

The fourth option, -12x+18y-6=0

Dividing by 3 we have

-4x+6y-2=0

Which could be the second dependent linear equation of 4x+6y-2=0 if there was no minus sign in the first term.

Hence, none of the above is the second linear dependent solution of the given equation 4x+6y-2=0.

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