Question

6. One number is 4 less than three times another number. If their sum is increased by 5, the result is 25. Find
both the numbers.
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Answer 1

$\huge\star\underline\mathfrak\green{AnsWer}$

Let the first number be x

Let the second number be y

According to given condition

$\sf{y= 3x-4}$

Also given that if sum is increased by $\sf{5}$ then result is $\sf{25}$.

So the equation can be written as

$\sf{x + y +5 = 25}$

Substituting the value of y we get

$\sf{=x + 3x – 5 + 5 = 25}$

$\sf{= 4x+1 = 25}$

$\sf{= 4x = 24}$

$\sf{= x = 6}$

Hence first number is $\sf 6$

Second Number = $\sf{y= 3 (6) -4 = 14}$

Answer 2

$\huge\star\underline\mathfrak\green{AnsWer}$

Let the first number be x

Let the second number be y

According to given condition

$\sf{y= 3x-4}$

Also given that if sum is increased by $\sf{5}$ then result is $\sf{25}$.

So the equation can be written as

$\sf{x + y +5 = 25}$

Substituting the value of y we get

$\sf{=x + 3x – 5 + 5 = 25}$

$\sf{= 4x+1 = 25}$

$\sf{= 4x = 24}$

$\sf{= x = 6}$

Hence first number is $\sf 6$

Second Number = $\sf{y= 3 (6) -4 = 14}$