Question

6. One number is 7 more than another and its square is 77 more than the square of the smaller num
What are the numbers?


7. The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36
Find the numbers

please answer both fast.​

Answer 1

Answer:

[ 6.]

Let x = the smaller number

Let x + 7 = the larger number

(x + 7)2 = x2 + 77

x2 + 14x + 49 = x2 + 77

14x = 28

x = 2

x + 7 = 9

[ 7.]

let first no. = x

and, second no. = (x +2)

(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8

Answer 2

Answer:

Let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8