Question

6. One of the factors of 42+y-y2 is​

Answer 1

Answer:

= -1(y^2-y-42)

= -1 (y^2-7y+6y-42)

= -1{y(y-7)+6(y-7)}

= -1((y-7)(y+6)

(-1)(y-7) and (y+6) are the factors

Answer 2

SOLUTION :

Given that,

$42 + y - {y}^{2}$

We can write it as :

$- {y}^{2} + y + 42$

${y}^{2} - y - 42$

Now,

We shall find the factor of this question by the method called middle term splitting.

${y}^{2} - (7 - 6)y - 42$

${y}^{2} - 7y + 6y - 42$

Now let's take common.

$y(y - 7) + 6(y - 7)$

$(y - 7)(y + 6)$

To find the factors, we have to equate these terms with zero.

So,

$y - 7 = 0 \\ y = 7$

Similarly,

$y + 6 = 0 \\ y = - 6$

Hence,

The factors are 7 and -6