Math, asked by jiyah79, 5 months ago

6. One of the parallel sides of a trapezium is thrice the
other. If the area and the height of the trapezium are
390 m2 and 15 m, respectively, find the lengths of the
parallel sides of the trapezium.

Answers

Answered by dkdkdkkdkdkdk

2

Answer:

6. One of the parallel sides of a trapezium is thrice the

other. If the area and the height of the trapezium are

390 m2 and 15 m, respectively, find the lengths of the

parallel sides of the trapezium.

Answered by manishawaghmaresarje

0

Answer:

vuv, ug, ug, ig, ihc

Step-by-step explanation:

gxigcob jv, ucjv, vi,

Previous Question

Next Question

Similar questions

Science, 2 months ago

Answer this question fast guys it's urgent ...

Chemistry, 2 months ago

n-Propanol on reaction with thionyl chloride gives...

Math, 2 months ago

Use each number 0-9 only once to complete the puzzle. Divisible by 3 and 9 0 Divisible by 4 and 6 6 Divisible by 2 and 5 7 Divisible by 4 and 9 9 1 6 Divisible by 3 and 5 9 1 Divisible by 2 and 9 5 4 Divisible by 6 and 5 3 0...

English, 5 months ago

plzz answer me.If u answer I will follow u...

Computer Science, 5 months ago

How can we make our presentation more interesting?

History, 11 months ago

Time: 01hr History Answer the following (1-2 words only) (10x1=10) a) When did Buddha die? b) Name the tree under which Buddha attained enlightenment, c) Who founded Jainism? d) Who was the son of Bimbisara? e) Alexander became the ruler of Macedonia in 1) tn k ingship was hereditary, g) Name the Greek general defeated by Chandragupta. h) Who was insulted and humiliated by Dhanananda...

Physics, 11 months ago

Two wires A and B are carrying currents I₁ and I₂ as shown in the figure. The separation between them is d. A third wire C carrying a current I is to be kept parallel to them at a distance x from A such that the net force acting on it is zero. The possible values of x are: (A) x = I₁/(I₁ – I₂)d and x = I₂/(I₁+I₂)d (B) x = ± I₂d/(I₁ – I₂) (C) x = I₂/(I₁ + I₂)d and x = I₂/(I₁– I₂)d (D) x =...

Physics, 11 months ago

The value of acceleration due to gravity at Earth’s surface is 9.8 ms⁻². The altitude above its surface at which the acceleration due to gravity decreases to 4.9 ms⁻², is close to: (Radius of earth = 6.4 × 10⁶ m) (A) 6.4 × 10⁶ m (B) 9.0 × 10⁶ m (C) 2.6 × 10⁶ m (D) 1.6 × 10⁶ m...