Math, asked by madhumangla2, 8 months ago

6 ouestion me last me 4 ke baad 4^-2 h​

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Answers

Answered by Anonymous
9

1)\huge\red{AnsWeR}

let the required no. be x

(3)-^7×x=>3

(1/3)^7×x=>3

1/2187×x=>3

x=>1/2187÷3

x=>1/2187×1/3

x=>6561

2)\huge\red{AnsWeR}

let the required no. be x

(-4)^5/x=>4^-2

-1024/x=>(1/4)^2

-1024/x=>1/16

x=>1/16×-1024

x=>1/4×-256

x=>1/1×-64

x=>-64

Answered by Dɪʏᴀ4Rᴀᴋʜɪ
12

1)\huge\blue{AnsWeR}

let the required no. be x

(3)-^7×x=>3

(1/3)^7×x=>3

1/2187×x=>3

x=>1/2187÷3

x=>1/2187×1/3

x=>6561

2)\huge\blue{AnsWeR}

let the required no. be x

(-4)^5/x=>4^-2

-1024/x=>(1/4)^2

-1024/x=>1/16

x=>1/16×-1024

x=>1/4×-256

x=>1/1×-64

x=>-64

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