Math, asked by Nabeela2407, 1 year ago

6 persons a,b,c,d,e,f are arranged in a row.find the conditional probability

shlokabhatt22: as we are asked Pr, we might as well consider A and B as a single entity, say Ü
so there are 5 entities, C D E F Ü
total permutations = 5! = 120
non-permissible permutations ( CD or DC together with the 3 others) = 2*4! = 48
indicated Pr = (120-48)/120 = 3/5

Answers

Answered by bhoirkunal000

there have only 5 alphabets this quetion is wrong

Answered by tardymanchester

Answer:

The conditional probability is 60%

Step-by-step explanation:

Given : 6 persons a,b,c,d,e,f are arranged in a row.

To find : The conditional probability

Solution :

Number of cases where a,b are together:

5! = 120 possibilities to order (ab),c,d,e,f

2! = 2 possibilities to order a and b within the (ab) subgroup

Total: 120 × 2= 240 cases

Number of cases where a, b and c, d are together:

4! = 24 possibilities to order (ab), (cd), e,f

2! = 2 possibilities to order a and b within the (ab) subgroup

2! = 2 possibilities to order c and d within the (cd) subgroup

Total: 96 cases

Probability that c and d are together knowing that a and b are together:

$\frac{96}{240} = 40\%$

Probability that c and d are separate knowing that a and b are together:

1 - 40% = 60%

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