Question

6 persons are to be accommodated in a conical tent. Each person required 15 m square place on the floor to sit and 150 m cube of air to breathe. Find the height of the tent ​

Answer 1

Answer:

I am giving you only the explanation of another sum related to this

Step-by-step explanation:

Area required by one person = 6 sq.m.

Area required by 10 persons = 6 \times 10 =60 m^26×10=60m2

So, Area of base conical tent = 60 sq.m.

Formula of Area of base of cone  = \pi r^2πr2

So, 60=3.14 \times r^260=3.14×r2

\frac{60}{3.14}=r^23.1460=r2

\sqrt{\frac{60}{3.14}}=r3.1460=r

4.37=r4.37=r

Volume of cone = \frac{1}{3} \pi r^2 h31πr2h

                          = \frac{1}{3} \times 3.14 \times (4.37)^2 h31×3.14×(4.37)2h  

Air required by 1 person = 30 cubic m

Air required by 10 person = 30 \times 10 =300 m^330×10=300m3

So, Volume of cone =  300 m^3300m3

So,  \frac{1}{3} \times 3.14 \times (4.37)^2 h=30031×3.14×(4.37)2h=300  

h=15.008h=15.008  

Hence the height of the cone is approximately 15 m

Answer 2

Answer: 30

Step-by-step explanation: