Question

6 pipes are required to fill a tank in 1 hour 20 minutes how long will it take if only 5 types of the same type are used in inverse proportion.

Answer 1

Answer:

6=80min

5= x

by cross multiple

6x =80×5

6x = 400

x =66.67

Answer 2

Solutions :

suppose the desired time to fill tank =x

thus, we have table:-

_____________________

Number of pipes | 6 | 5

______________|___|____

time (in minute) | 80 | x

______________|___|____

Lesser the number of pipes, more will be the time required by it to fill the tank. so, this is a case of inverse proportion.

Hence,

80 × 6 = x × 5. ---------------[x1y2 = x2y2]

or,

80 ×6/5

= 5

x= 96

thus, time taken to fill the tank by 5 pipes is 96 minute or 1hour 36 minute .