6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take, if only 5 pipes of the same type are used.
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Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 6 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Hence, 80 × 6 = x × 5
⇒ 80×6/5 = x
⇒x = 96
Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes
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