6 pipes are required to fill a tank in 1 hour 20 minutes. If we use 5 such types of pipes, how much time it will take to fill the tank?
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Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 6 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Hence, 80×6=x×5
⇒
5
80×6
=x
⇒x=96
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