Question

 6 pipes are required to fill a tank in 1 hour 20 minutes. If we use 5 such types of pipes, how much time it will take to fill the tank? don't spam solve Step by step otherwise reported​

Answer 1

$\huge{\underline{\mathfrak{Answer:-}}}$

Let the desired time to fill the tank be x minutes.

In 80 mins a tank is filled by 6 pipes

Lesser the number of pipes more will be the time required by it to fill the tank.

So, this is a case of inverse proportion.

Hence, 80×6=x×5

⇒80×6 /5 =x

⇒x=96

Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.

Answer 2

Answer:

Let the desired time to fill the tank be x minutes.

In 80 mins a tank is filled by 6 pipes

Lesser the number of pipes more will be the time required by it to fill the tank.

So, this is a case of inverse proportion.

Hence, 80×6=x×5

⇒80×6 /5 =x

⇒x=96

Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.