Question

6 pipes are required to fill a tank in 1 hour 20mins. how long will it take if only 5 pipes of the same type are used?????????????????.​

Answer 1

$\underbrace \text{Answer:}$

Let's first convert hour to minute.

1hour 20mins = 1×60+20

⟶ 60+20min

⟶ 80mins

Now,

Let the time be "x" min

As we increased the number of pipes, the time taken to fill the tank decrease.

⛬ Number of pipes and time taken are in inverse proportion.

$⟶ \bold{6×80=5×x}$

$⟶ \bold{ \frac{6 \times \cancel{80}}{ \cancel{5} }= x }$

$⟶ \bold{x = 6 \times 16}$

$⟶ \bold{x = 96min}$

Now,

Convert the min to hour.

$\bold{x = \frac{96}{60}hour }$

$\bold{x = 1hour \: 36min}$

Therefore, 5 pipes will find the tank in 1hour 36min.

Answer 2

Answer:

96 mins

Step-by-step explanation: