Question

6 pipes are required to fill a tank in 80 minutes. If we use 5 such types of pipes, how much time it will take to fill the tank? *


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Answer 1

Answer:

96 minutes

Step-by-step explanation:

Time taken by 6 pipes to fill a tank = 80 minutes

Time taken by 1 pipe to fill a tank = 80×6 = 480 minutes

Tim taken by 5 pipes to fill a tank = 480/5 = 96 minutes

Answer 2

Given :

• 6 pipes are required to fill a tank in 80 minutes.

What we have to do ?

Here, first you have to know the unitary Method. According to the unitary method, if the pipes increase in number then it will take lesser time to fill the tank and if number of pipes decrease then it will take more time as compare to the first condition. In simple words, this is inverse proportional concept.

Let's do it now !

First we will consider the time taken by 5 pipes to fill the same tank in terms of variable { x , y , z... so on } and then we will multiply and divide the no. of pipe and the we will get our answer.

$\dag\:\underline{\sf Solution :}$

No. of pipes ↑ ⠀⠀⠀⠀⠀Time Taken ↓

Now,

Let we consider the time taken be ' x " minutes.

$\bigstar\:\underline{\textbf{As per the Question :}}$

No. of Pipes ⠀⠀⠀⠀⠀⠀Time Taken

⠀⠀ 6⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀80 min

⠀⠀5 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀' x ' min

$:\implies\sf 6 \times 80 = 5 \times x$

$:\implies\sf 480 = 5x$

$:\implies\sf x = \dfrac{480}{5}$

$:\implies\sf x = 96$

$:\implies \underline{ \boxed{\textsf{ \textbf{ Time \: Taken \: by \: 5 \: Pipes = 96 \: Minutes }}}}$

Hence, 5 pipes take 1 hour 36 minutes to fill the same tank.