Question

6) PQRS is a parallelogram of area 120 cm: If PS = 10 cm and PQ = 15 cm find the measures of SM and altitude PM . ​

Answer 1

Answer:

PM = 8 cm SM = 6cm

Step-by-step explanation:

Area of parallelogram = 120 cm² = 15 × PM

PM = 8 cm

Now in trinagle PMS

PS^2 = SM² + PM^2

10^2 = SM² + 8^2

SM = 10^2 - 8^2 = 6 cm