Question

(6)prove that 1/sec0-tan0= sec0+tan0
​

Answer 1

We have,

1/(secø-tanø)

1x(secø+tanø)/(secø-tanø)×secø+tanø

secø+tanø/(sec²ø-tan²ø)

secø+tanø/(1+tan²ø-tan²ø) [sec²ø=1+tan²ø]

secø+tanø/1

=rhs

this

is your answer

Answer 2

Answer:

Step-by-step explanation:

LHS=