Question

6. Prove that 6,8,10 form pythogerian triplets.​

Answer 1

Answer:

(Ac)2= (AB) 2+ (BC)

(10) 2= (6) 2+ (8) 2

100= 36+ 64

100=100

Answer 2

Pythagorian Triplets :

m^2 + n^2 = p^2

6^2 + 8^2 = 10^2

36 + 64 = 100

So, ( 6, 8, 10 ) form Pythagorian Triplets..

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