6.) Prove that
i)∆ABC is congruent to ∆ADC
ii) angle B = angle D
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AD is parallel to BC and AC is the transverse
<DAC=<BCA
<BAC=<DCA[alternative angles]
In ∆ABC and ∆ADC,
- <DAC=<BCA
- <BAC=<DCA
- AC is the common arm
by A-S-A rule of congruency, both the triangles are congruent to eachother
As they are congruent, angle B=angle D
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