Question

6. Prove that :
(i) sin 60° = 2 sin 30° cos 30º.
(ii) 4 (sin4 30° + cos + 60°)
- 3 (cos? 45° - sin? 90°) = 2
7. (i) If sin x = cos x and x is acute, state
value of​

Answer 1

1)sin 60=2 sin 30 degree cos 30 degree

LHS=2*1/2*√3/2

=√3/2

RHS= sin 60

=√3/2

thus LHS=RHS

hence proved