-6) Prove that tan(1/2 sin^-1 3/4)=4-1773
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Let tan
−1
(1)=x
⇒1=tanx
Let tan
−1
(2)=y
⇒2=tany
Let tan
−1
(3)=z
⇒3=tanz
tan(x+y+z)=
1−tanx.tany−tanx.tanz−tany.tanz
tanx+tany+tanz−tanx.tany.tanz
=
1−1×2−1×3−2×3
1+2+3−1×2×3
=0
⇒x+y+z=π
tan
−1
(1)+tan
−1
(2)+tan
−1
(3)=π
( x+y+z cannot be equal to zero, because
tan
−1
(1)+tan
−1
(2)+tan
−1
(3) will have some value greater than zero )
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