6 pumps of kirlosker can fill a tank in 7 days and 2 similar pumps of USHA can fill the same tank in 18 days. what is the ratio of the efficiency of a kirlosker pump and a USHA pump?
A) 6:7 B) 7:6 C) 7:54 D) None of these
Answers
Answered by
0
Answer:
7:6 is the answer for the given problem
Step-by-step explanation:
6 pumps can fill a tank in 7 days
2 pumps can fill the same tank in 18 days
we know that , m1=6,d1 =7,m2 =2,d2 =18
m1d1 :m2d2= 6×7:2×18=42:36=7:6
Answered by
0
Answer:
CORRECT OPTION IS:(A) 6:7
Explanation:
The number of days required by a single Kirlosker pump to fill the tank =6×7=42 days and the number of days required by a single USHA pump to fill the same tanks=2×18=36days. Now, since efficiency is inversely proportional to the number of days. Hence,
(Efficiency of one K-pump)/(Efficiency of U-pump)=36/42=6/7
HOPE THIS HELPS YOU
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